Equação de Peng/Robinson:
σ : = 1 + 2
ε : = 1 - 2
Ω : = 0.07779
Ψ : = 0.45724
c : = b . 37464 + 1.54226 ⋅ ω - 0.26992 ) ⋅ ω 2 ¯
α : = 1 + c ⋅ 1 ^ - T r ) 0.5 2
β Ω = P r T r →
Eq. (3.53)
q : = Ψ ω Ω ⋅ T r ¯
Eq. (3.54)
Achados:
z : = 1
Dados:
z = 1 + β - q ⋅ β ⋅ z - β ( t + ε β ⋅ ( z + σ β )
Eq. (3.52)
Z ( β , q ) : = E n c o n t r e ( z )
i : = 1 . . 4
I i : = 1 2 ⋅ 2 ⋅ l n Z β i , q i + σ β i Z β i , q i + ε β i E q . ( 6.65 b )
H R i : = R ⋅ T 1 i Z β i , q i ) - 1 - c i T r i 0.5 α i + 1 ⋅ q i I i
Eq. (6.67)
S R i : = R ⋅ l n z β i , q i ) - β i - c i ⋅ ⋅ T r i α i 0.5 ⋅ q i I I )
Eq. (6.68)
A derivada nessas equações é igual a:
- c i ' T r 1 α i 0.5
Agora iterate para T2
T2 : = 270 297 229 383
K
Z β i , q i
)=
H R = - 3.041 - 2.459 - 0.6 - 1.581 k J m o l
S R = - 6.152 - 4.784 - 1.847 - 2.689 J m o l ⋅ K
τ : = T 2 → T 1
C p : = R ⋅ A + B 2 ⋅ T 1 ⋅ 0 + 1 + C 3 ⋅ τ 1 2 ⋅ ( ) 2 + τ + 1 + D τ ⋅ T 1 2 ¯
T 2 : = H R C p + T 1 →
T 2 = 269.735 297.366 229.32 382.911 K
Δ S : = C p ⋅ l n T 2 T 1 - R ⋅ l n P 2 P 1 - S R
Δ S = 31.2 29.694 31.865 22.04 J m o l ⋅ K