A piston PDP has a 5-in diameter and a 2-in stroke and

operates at 750 r/min with 92 percent volumetric efficiency.

(a) What is its delivery, in gal/min? (b) If the pump delivers

SAE 10W oil at 208C against a head of 50 ft, what horsepower is required when the overall effi ciency is 84 percent?

Passo 1

Saaaalve, tranquilo? Vamos lá resolver mais uma questão juntos?! 😊

Os dados são os seguintes:

Diâmetro do pistão: d = 5 Acesso: L = 2 emVelocidade: N = 750 r / m i n Eficiência volumétrica: η v o l = 92 %

Passo 2

O volume deslocado é dado por

v = π 4 d 2 L   = π 4 ( 5 ) 2 ( 2 )   = 39.269 i n 3

Passo 3

Portanto, a taxa de fluxo de volume em g p m / m i n

Q = 117.3 g a l m i n

A entrega em gal/min é Q = 117.3 g a l m i n

Passo 4

b) Se a bomba fornece óleo SAE 10W / m i n contra uma cabeça de 50 f t então 20 C para o óleo SAE 10W a 20 C, tome ρ = 870   k g / m 3 ≈ 1.688 s l u g / f t 3

A potência da bomba é dada por

P = ρ g Q H η   = 1.688 × 32.2 × 117.3 449 f t 3   s × 50 0.84   = 845.2 f t ⋅ l b f s   = 845.2 550 h p   = 1.536 h p

A potência do cavalo é necessária P = 1.536 h p


a) Q = 117.3 g a l m i n

b) P = 1.536 h p

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