\begin{gathered} H=\operatorname{span}\{(-3,1,-2),(5,-2,6)\} \text { e } \\\ M=\operatorname{span}\{(2,10,1)\} \end{gathered}
Encontre o único vetor \vec{x} \in M^{\perp} \cap H da forma \vec{x}=\left(-3, x_{2}, x_{3}\right). O valor de x_{3} é:
(A) 4
(B) 5
(C) 6
(D) 7
(E) 8
(F) 9
(G) 10
(H) 11